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This is the place for general discussions - we are a family site - no bad language, no flames.
A Moderators word is final.

1) Go to the link below. After reading each window click on the boy in the lower right corner.
2) In the last window type in your answer in the white box using the keyboard (there is an invisible cursor in the middle of the box....so just type it in). You will be amazed....and no, I don't know how it's done .

MrC

MrCharlie
Visiting Master

Posts: 44
Joined: March 5th, 2005, 7:43 am
Location: Central New Jersey, USA
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What!!!!!!!!!!1

OMG!!!! This evil....

Aamazing!

MPRep
Regular Member

Posts: 217
Joined: January 29th, 2006, 11:04 pm

That is ..... Definitely Amazing
How, I'd sure love to know that one.
Wonder if any get the same answer:
9

turtledove

Posts: 4398
Joined: February 13th, 2006, 3:26 am
Location: California

Heh... he got mine wrong

'KotaGuy

Posts: 12472
Joined: April 7th, 2005, 7:06 pm

Maybe you didn't follow instructions Kota

I've donde this more than ten times and it always returns the right answer...

For instance:
I chose the following number 7699, jumbled --> 9796
subtraction: 9796 - 7699 = 2097
I circled number nine, jumbled ----> 702
Typed in 702 and fido answered 9

I guess the addition of your last number gives out the number you circled.

Let me see that again:
I chose the following number 3865, jumbled --> 8365
subtraction: 8365 - 3856 = 4509
I circled number five, jumbled ----> 094
Typed in 94 and fido answered 5!

Ok now I see, when the addition of your last number is greater than 9, then it subtracts. 9 - 4 = 5

Ok so what if you end up with the same digit (except for the zero of course)
1478, 4781, 4781 - 1478 = 3303, you should enter 303, 330, 33
fido's answer will be 3 always.

What if you end up with a 3 digit number with no zeros in it?
9732 - 2379 = 7353
circled number 5, jumble ---> 337
If I enter 357 then fido's answer is 3....I can't see the pattern
Ok I need some help with this

So cracking the code, so far
• remove the zeros
• if digits are all the same
• then output: the repeating digit
• else somewhere in here we must deal with the number 3,3,5,7 lol
• sum = sum of all digits
• if sum < 9
• then output: sum
• else

Keep trying

MPRep
Regular Member

Posts: 217
Joined: January 29th, 2006, 11:04 pm

Nicely worked MPRep,
Thanks
I'll be trying it again too; along with a friend or two.

turtledove

Posts: 4398
Joined: February 13th, 2006, 3:26 am
Location: California

Yeah... mustve done something wrong the first time... its been right every other time...

Kinda spooky

'KotaGuy

Posts: 12472
Joined: April 7th, 2005, 7:06 pm

i thought he got mine wrong, and then i realized i had subtracted wrong

mindboggling!!!

agrarianmonk
MRU Teacher Emeritus

Posts: 5439
Joined: December 24th, 2005, 3:11 am

got this from a friend:

basically any two numbers that are subtracted from each other, with the same digits, will always be divisible by 9

numbers divisible by 9 will have all their rearranged versions divisble by 9 also

so say you end up with the number 1467. if you circled 6, the game will ask you to enter 147, or any combination of that like 741. then its programmed to check 7411, 7412, 7413....7419

only 7416 will be divisible by 9, so it knows that the number you left out (and hence circled) was a 6

agrarianmonk
MRU Teacher Emeritus

Posts: 5439
Joined: December 24th, 2005, 3:11 am

Bringing back memories of maths lessons, not sure if thats a good thing

Still very good site

GS2
Regular Member

Posts: 964
Joined: February 17th, 2006, 8:34 pm
Location: Bedfordshire

wow, thx agrarianmonk, that's much more simple than my incomplete algorithm

Now the question is, how to demonstrate that the answer will always be divisible by 9?
More maths lessons as fogleg says

MPRep
Regular Member

Posts: 217
Joined: January 29th, 2006, 11:04 pm

Instead of testing through the possible range, just divide the given number by nine and take the remainder away from nine for the answer. For example, 7431 - 1743 = 5688. Circle an 8 and jumble the rest, say 685. Divide this by nine leaves a remainder of 1. Subtract this from nine and there you go! Sounds complicated but you can do the calculation fairly quickly after some practice.

However, there are certain situations where two numbers could be divisible by 9. Let's take the number 3069. If we circle the 9 and jumble to, say 603, this divides exactly with no remainder (zero). Therefore zero from nine is nine. It works! BUT, if you were to circle the zero and jumble, say 693, this is also divisible exactly by nine and, from the previous example, we would guess incorrectly that the answer was nine. Now we know why it asks you not to circle a zero.

Vino Rosso

Posts: 9024
Joined: April 24th, 2006, 8:36 am
Location: Gloria Jean's in Murray St. Mall (I wish!)

### Function of 9's

It also uses the symbol to represent the 9th place throughout the table. It also changes the position each time so that no matter how many times you attempt the challlenge it varies. However, the symbol always ends up with a position divisable by 9.
Chuck2
Regular Member

Posts: 26
Joined: September 19th, 2006, 10:27 pm

Amazing, got mine right

Mr_JAk3
MRU Teacher Emeritus

Posts: 3023
Joined: April 16th, 2006, 1:52 pm
Location: Finland
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