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Boggle Your Mind!

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Boggle Your Mind!

Unread postby MrCharlie » April 30th, 2006, 12:45 pm

This will boggle your mind... Take your time and follow the instructions.

1) Go to the link below. After reading each window click on the boy in the lower right corner.
2) In the last window type in your answer in the white box using the keyboard (there is an invisible cursor in the middle of the box....so just type it in). You will be amazed....and no, I don't know how it's done .

Click here: http://digicc.com/fido/

MrC
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Unread postby MPRep » April 30th, 2006, 12:51 pm

What!!!!!!!!!!1

OMG!!!! This evil....:sign5:

Aamazing!
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Unread postby turtledove » April 30th, 2006, 4:10 pm

That is ..... :shock: Definitely Amazing :!:
How, I'd sure love to know that one.
Thanks for the link :D
Wonder if any get the same answer:
9 ;)
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Unread postby 'KotaGuy » April 30th, 2006, 4:40 pm

Heh... he got mine wrong :)
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Unread postby MPRep » April 30th, 2006, 11:41 pm

Maybe you didn't follow instructions Kota :P

I've donde this more than ten times and it always returns the right answer... :shock:

For instance:
I chose the following number 7699, jumbled --> 9796
subtraction: 9796 - 7699 = 2097
I circled number nine, jumbled ----> 702
Typed in 702 and fido answered 9

I guess the addition of your last number gives out the number you circled.

Let me see that again:
I chose the following number 3865, jumbled --> 8365
subtraction: 8365 - 3856 = 4509
I circled number five, jumbled ----> 094
Typed in 94 and fido answered 5!

Ok now I see, when the addition of your last number is greater than 9, then it subtracts. 9 - 4 = 5

Ok so what if you end up with the same digit (except for the zero of course)
1478, 4781, 4781 - 1478 = 3303, you should enter 303, 330, 33
fido's answer will be 3 always.

What if you end up with a 3 digit number with no zeros in it?
9732 - 2379 = 7353
circled number 5, jumble ---> 337
If I enter 357 then fido's answer is 3....I can't see the pattern :?
Ok I need some help with this

So cracking the code, so far :lol:
  • remove the zeros
  • if digits are all the same
    • then output: the repeating digit
    • else somewhere in here we must deal with the number 3,3,5,7 lol
      • sum = sum of all digits
      • if sum < 9
        • then output: sum
        • else


Keep trying ;)
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Unread postby turtledove » May 1st, 2006, 12:21 am

Nicely worked MPRep,
Thanks :D
I'll be trying it again too; along with a friend or two.
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Unread postby 'KotaGuy » May 1st, 2006, 12:33 am

Yeah... mustve done something wrong the first time... its been right every other time...

Kinda spooky :P
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Unread postby agrarianmonk » May 1st, 2006, 2:33 am

i thought he got mine wrong, and then i realized i had subtracted wrong :lol:

mindboggling!!! :)
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Unread postby agrarianmonk » May 1st, 2006, 3:59 pm

got this from a friend:

basically any two numbers that are subtracted from each other, with the same digits, will always be divisible by 9

numbers divisible by 9 will have all their rearranged versions divisble by 9 also

so say you end up with the number 1467. if you circled 6, the game will ask you to enter 147, or any combination of that like 741. then its programmed to check 7411, 7412, 7413....7419

only 7416 will be divisible by 9, so it knows that the number you left out (and hence circled) was a 6
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Unread postby GS2 » May 1st, 2006, 4:49 pm

Bringing back memories of maths lessons, not sure if thats a good thing :oops:

Still very good site :)
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Unread postby MPRep » May 1st, 2006, 9:24 pm

wow, thx agrarianmonk, that's much more simple than my incomplete algorithm :P

Now the question is, how to demonstrate that the answer will always be divisible by 9? :lol:
More maths lessons as fogleg says :D
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Unread postby Vino Rosso » May 2nd, 2006, 9:21 am

Instead of testing through the possible range, just divide the given number by nine and take the remainder away from nine for the answer. For example, 7431 - 1743 = 5688. Circle an 8 and jumble the rest, say 685. Divide this by nine leaves a remainder of 1. Subtract this from nine and there you go! Sounds complicated but you can do the calculation fairly quickly after some practice.
:study:
However, there are certain situations where two numbers could be divisible by 9. Let's take the number 3069. If we circle the 9 and jumble to, say 603, this divides exactly with no remainder (zero). Therefore zero from nine is nine. It works! BUT, if you were to circle the zero and jumble, say 693, this is also divisible exactly by nine and, from the previous example, we would guess incorrectly that the answer was nine. Now we know why it asks you not to circle a zero.
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Function of 9's

Unread postby Chuck2 » September 26th, 2006, 3:33 pm

Recently I received the following url: http://www.milaadesign.com/wizardy.html
It also uses the symbol to represent the 9th place throughout the table. It also changes the position each time so that no matter how many times you attempt the challlenge it varies. However, the symbol always ends up with a position divisable by 9.
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Unread postby Mr_JAk3 » September 27th, 2006, 4:50 am

Amazing, got mine right :shock:
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